10330130021 has 2 divisors, whose sum is σ = 10330130022. Its totient is φ = 10330130020.

The previous prime is 10330130009. The next prime is 10330130023. The reversal of 10330130021 is 12003103301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6418252996 + 3911877025 = 80114^2 + 62545^2 .

It is a cyclic number.

It is not a de Polignac number, because 10330130021 - 2²⁶ = 10263021157 is a prime.

Together with 10330130023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10330129978 and 10330130005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10330130023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5165065010 + 5165065011.

It is an arithmetic number, because the mean of its divisors is an integer number (5165065011).

Almost surely, 2^10330130021 is an apocalyptic number.

It is an amenable number.

10330130021 is a deficient number, since it is larger than the sum of its proper divisors (1).

10330130021 is an equidigital number, since it uses as much as digits as its factorization.

10330130021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 10330130021 its reverse (12003103301), we get a palindrome (22333233322).

The spelling of 10330130021 in words is "ten billion, three hundred thirty million, one hundred thirty thousand, twenty-one".