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103310213009 is a prime number
BaseRepresentation
bin110000000110111000…
…1001011111110010001
3100212122212101120211112
41200031301023332101
53143034403304014
6115243212223105
710315060215203
oct1401561137621
9325585346745
10103310213009
113a8a4a16133
121803246aa95
139985559573
145000938773
152a49b5873e
hex180dc4bf91

103310213009 has 2 divisors, whose sum is σ = 103310213010. Its totient is φ = 103310213008.

The previous prime is 103310212991. The next prime is 103310213011. The reversal of 103310213009 is 900312013301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95498304784 + 7811908225 = 309028^2 + 88385^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103310213009 is a prime.

It is a super-2 number, since 2×1033102130092 (a number of 23 digits) contains 22 as substring.

Together with 103310213011, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (103310213309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51655106504 + 51655106505.

It is an arithmetic number, because the mean of its divisors is an integer number (51655106505).

Almost surely, 2103310213009 is an apocalyptic number.

It is an amenable number.

103310213009 is a deficient number, since it is larger than the sum of its proper divisors (1).

103310213009 is an equidigital number, since it uses as much as digits as its factorization.

103310213009 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

The spelling of 103310213009 in words is "one hundred three billion, three hundred ten million, two hundred thirteen thousand, nine".