103333131121 has 4 divisors (see below), whose sum is σ = 112727052144. Its totient is φ = 93939210100.

The previous prime is 103333131101. The next prime is 103333131127. The reversal of 103333131121 is 121131333301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103333131121 - 2⁷ = 103333130993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103333131092 and 103333131101.

It is not an unprimeable number, because it can be changed into a prime (103333131127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4696960495 + ... + 4696960516.

It is an arithmetic number, because the mean of its divisors is an integer number (28181763036).

Almost surely, 2^103333131121 is an apocalyptic number.

103333131121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

103333131121 is a deficient number, since it is larger than the sum of its proper divisors (9393921023).

103333131121 is an equidigital number, since it uses as much as digits as its factorization.

103333131121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9393921022.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 103333131121 its reverse (121131333301), we get a palindrome (224464464422).

The spelling of 103333131121 in words is "one hundred three billion, three hundred thirty-three million, one hundred thirty-one thousand, one hundred twenty-one".