Base | Representation |
---|---|
bin | 110000001000000111… |
… | …0000100111001001101 |
3 | 100212202201210002022102 |
4 | 1200100032010321031 |
5 | 3143130420344441 |
6 | 115251241524445 |
7 | 10316066620604 |
oct | 1402016047115 |
9 | 325681702272 |
10 | 103351340621 |
11 | 3a9161569a1 |
12 | 180441a3725 |
13 | 9990c29429 |
14 | 50061a2a3b |
15 | 2a4d57e69b |
hex | 1810384e4d |
103351340621 has 2 divisors, whose sum is σ = 103351340622. Its totient is φ = 103351340620.
The previous prime is 103351340593. The next prime is 103351340623. The reversal of 103351340621 is 126043153301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54016267396 + 49335073225 = 232414^2 + 222115^2 .
It is a cyclic number.
It is not a de Polignac number, because 103351340621 - 218 = 103351078477 is a prime.
Together with 103351340623, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103351340623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51675670310 + 51675670311.
It is an arithmetic number, because the mean of its divisors is an integer number (51675670311).
Almost surely, 2103351340621 is an apocalyptic number.
It is an amenable number.
103351340621 is a deficient number, since it is larger than the sum of its proper divisors (1).
103351340621 is an equidigital number, since it uses as much as digits as its factorization.
103351340621 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 103351340621 its reverse (126043153301), we get a palindrome (229394493922).
The spelling of 103351340621 in words is "one hundred three billion, three hundred fifty-one million, three hundred forty thousand, six hundred twenty-one".
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