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103351540053 = 3149231211499
BaseRepresentation
bin110000001000000111…
…0110101100101010101
3100212202202011012212210
41200100032311211111
53143130443240203
6115251250104033
710316101411206
oct1402016654525
9325682135783
10103351540053
113a916282813
121804427b019
139990c99138
1450062155ad
152a4d5bd803
hex18103b5955

103351540053 has 8 divisors (see below), whose sum is σ = 138726900000. Its totient is φ = 68438603408.

The previous prime is 103351540049. The next prime is 103351540063. The reversal of 103351540053 is 350045153301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 103351540053 - 22 = 103351540049 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 103351540053.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103351540013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 115605303 + ... + 115606196.

It is an arithmetic number, because the mean of its divisors is an integer number (17340862500).

Almost surely, 2103351540053 is an apocalyptic number.

It is an amenable number.

103351540053 is a deficient number, since it is larger than the sum of its proper divisors (35375359947).

103351540053 is a wasteful number, since it uses less digits than its factorization.

103351540053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231211651.

The product of its (nonzero) digits is 13500, while the sum is 30.

Adding to 103351540053 its reverse (350045153301), we get a palindrome (453396693354).

The spelling of 103351540053 in words is "one hundred three billion, three hundred fifty-one million, five hundred forty thousand, fifty-three".

Divisors: 1 3 149 447 231211499 693634497 34450513351 103351540053