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10341433111 is a prime number
BaseRepresentation
bin10011010000110010…
…11011111100010111
3222200201020020022011
421220121123330113
5132134401324421
64430100445051
7514161505522
oct115031337427
928621206264
1010341433111
114427518839
1220073a9787
13c8a6641b9
1470163dbb9
15407d534e1
hex26865bf17

10341433111 has 2 divisors, whose sum is σ = 10341433112. Its totient is φ = 10341433110.

The previous prime is 10341433079. The next prime is 10341433133. The reversal of 10341433111 is 11133414301.

It is an a-pointer prime, because the next prime (10341433133) can be obtained adding 10341433111 to its sum of digits (22).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10341433111 - 25 = 10341433079 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10341433181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170716555 + 5170716556.

It is an arithmetic number, because the mean of its divisors is an integer number (5170716556).

Almost surely, 210341433111 is an apocalyptic number.

10341433111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10341433111 is an equidigital number, since it uses as much as digits as its factorization.

10341433111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 10341433111 its reverse (11133414301), we get a palindrome (21474847412).

The spelling of 10341433111 in words is "ten billion, three hundred forty-one million, four hundred thirty-three thousand, one hundred eleven".