Base | Representation |
---|---|
bin | 110000001010001100… |
… | …0001111100001000001 |
3 | 100212221121001221222200 |
4 | 1200110120033201001 |
5 | 3143301301130213 |
6 | 115302213223413 |
7 | 10320604653030 |
oct | 1402430174101 |
9 | 325847057880 |
10 | 103421114433 |
11 | 3a951582aaa |
12 | 18063631b69 |
13 | 99a2519000 |
14 | 5011566717 |
15 | 2a54763273 |
hex | 181460f841 |
103421114433 has 48 divisors (see below), whose sum is σ = 184947934080. Its totient is φ = 54551723616.
The previous prime is 103421114417. The next prime is 103421114477. The reversal of 103421114433 is 334411124301.
103421114433 is a `hidden beast` number, since 1 + 0 + 3 + 4 + 211 + 1 + 443 + 3 = 666.
It is not a de Polignac number, because 103421114433 - 24 = 103421114417 is a prime.
It is a super-2 number, since 2×1034211144332 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103421114397 and 103421114406.
It is not an unprimeable number, because it can be changed into a prime (103421114633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 235191 + ... + 512012.
It is an arithmetic number, because the mean of its divisors is an integer number (3853081960).
Almost surely, 2103421114433 is an apocalyptic number.
103421114433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
103421114433 is a deficient number, since it is larger than the sum of its proper divisors (81526819647).
103421114433 is an equidigital number, since it uses as much as digits as its factorization.
103421114433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 747255 (or 747226 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 103421114433 its reverse (334411124301), we get a palindrome (437832238734).
The spelling of 103421114433 in words is "one hundred three billion, four hundred twenty-one million, one hundred fourteen thousand, four hundred thirty-three".
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