103433301131 has 4 divisors (see below), whose sum is σ = 106769859264. Its totient is φ = 100096743000.

The previous prime is 103433301091. The next prime is 103433301149. The reversal of 103433301131 is 131103334301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131103334301 = 53 ⋅2473647817.

It is a cyclic number.

It is not a de Polignac number, because 103433301131 - 2²² = 103429106827 is a prime.

It is a super-2 number, since 2×103433301131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103433301097 and 103433301106.

It is not an unprimeable number, because it can be changed into a prime (103433301151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668279020 + ... + 1668279081.

It is an arithmetic number, because the mean of its divisors is an integer number (26692464816).

Almost surely, 2^103433301131 is an apocalyptic number.

103433301131 is a deficient number, since it is larger than the sum of its proper divisors (3336558133).

103433301131 is an equidigital number, since it uses as much as digits as its factorization.

103433301131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3336558132.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 103433301131 its reverse (131103334301), we get a palindrome (234536635432).

The spelling of 103433301131 in words is "one hundred three billion, four hundred thirty-three million, three hundred one thousand, one hundred thirty-one".