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103494992893 is a prime number
BaseRepresentation
bin110000001100011001…
…0000100001111111101
3100220010202002101011221
41200120302010033331
53143424204233033
6115313412513341
710322462632105
oct1403062041775
9326122071157
10103494992893
113a98a252a86
121808431b851
1399b4914c86
14501b2b8205
152a5aea812d
hex1818c843fd

103494992893 has 2 divisors, whose sum is σ = 103494992894. Its totient is φ = 103494992892.

The previous prime is 103494992873. The next prime is 103494992981. The reversal of 103494992893 is 398299494301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60379792729 + 43115200164 = 245723^2 + 207642^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103494992893 is a prime.

It is a super-2 number, since 2×1034949928932 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103494992813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51747496446 + 51747496447.

It is an arithmetic number, because the mean of its divisors is an integer number (51747496447).

Almost surely, 2103494992893 is an apocalyptic number.

It is an amenable number.

103494992893 is a deficient number, since it is larger than the sum of its proper divisors (1).

103494992893 is an equidigital number, since it uses as much as digits as its factorization.

103494992893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15116544, while the sum is 61.

The spelling of 103494992893 in words is "one hundred three billion, four hundred ninety-four million, nine hundred ninety-two thousand, eight hundred ninety-three".