1035254431331 has 2 divisors, whose sum is σ = 1035254431332. Its totient is φ = 1035254431330.

The previous prime is 1035254431303. The next prime is 1035254431333. The reversal of 1035254431331 is 1331344525301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1035254431331 - 2²² = 1035250237027 is a prime.

It is a super-2 number, since 2×1035254431331² (a number of 25 digits) contains 22 as substring.

Together with 1035254431333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1035254431291 and 1035254431300.

It is not a weakly prime, because it can be changed into another prime (1035254431333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517627215665 + 517627215666.

It is an arithmetic number, because the mean of its divisors is an integer number (517627215666).

Almost surely, 2^{1035254431331} is an apocalyptic number.

1035254431331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1035254431331 is an equidigital number, since it uses as much as digits as its factorization.

1035254431331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 1035254431331 its reverse (1331344525301), we get a palindrome (2366598956632).

The spelling of 1035254431331 in words is "one trillion, thirty-five billion, two hundred fifty-four million, four hundred thirty-one thousand, three hundred thirty-one".