103540131535 has 4 divisors (see below), whose sum is σ = 124248157848. Its totient is φ = 82832105224.

The previous prime is 103540131529. The next prime is 103540131557. The reversal of 103540131535 is 535131045301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103540131535 - 2⁵ = 103540131503 is a prime.

It is a super-3 number, since 3×103540131535³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103540131497 and 103540131506.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10354013149 + ... + 10354013158.

It is an arithmetic number, because the mean of its divisors is an integer number (31062039462).

Almost surely, 2^103540131535 is an apocalyptic number.

103540131535 is a deficient number, since it is larger than the sum of its proper divisors (20708026313).

103540131535 is an equidigital number, since it uses as much as digits as its factorization.

103540131535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20708026312.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 103540131535 its reverse (535131045301), we get a palindrome (638671176836).

The spelling of 103540131535 in words is "one hundred three billion, five hundred forty million, one hundred thirty-one thousand, five hundred thirty-five".