Base | Representation |
---|---|
bin | 10011010010010100… |
… | …01100000011110101 |
3 | 222201121021112011102 |
4 | 21221022030003311 |
5 | 132201134304414 |
6 | 4431234415445 |
7 | 514405234142 |
oct | 115112140365 |
9 | 28647245142 |
10 | 10354213109 |
11 | 4433757619 |
12 | 200b731585 |
13 | c901ba226 |
14 | 7032093c9 |
15 | 409029ede |
hex | 26928c0f5 |
10354213109 has 2 divisors, whose sum is σ = 10354213110. Its totient is φ = 10354213108.
The previous prime is 10354213081. The next prime is 10354213141. The reversal of 10354213109 is 90131245301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5412544900 + 4941668209 = 73570^2 + 70297^2 .
It is an emirp because it is prime and its reverse (90131245301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10354213109 - 224 = 10337435893 is a prime.
It is a super-3 number, since 3×103542131093 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10354213159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177106554 + 5177106555.
It is an arithmetic number, because the mean of its divisors is an integer number (5177106555).
Almost surely, 210354213109 is an apocalyptic number.
It is an amenable number.
10354213109 is a deficient number, since it is larger than the sum of its proper divisors (1).
10354213109 is an equidigital number, since it uses as much as digits as its factorization.
10354213109 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 29.
The spelling of 10354213109 in words is "ten billion, three hundred fifty-four million, two hundred thirteen thousand, one hundred nine".
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