10354213141 has 2 divisors, whose sum is σ = 10354213142. Its totient is φ = 10354213140.

The previous prime is 10354213109. The next prime is 10354213147. The reversal of 10354213141 is 14131245301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5317472241 + 5036740900 = 72921^2 + 70970^2 .

It is a cyclic number.

It is not a de Polignac number, because 10354213141 - 2⁵ = 10354213109 is a prime.

It is a super-3 number, since 3×10354213141³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10354213147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177106570 + 5177106571.

It is an arithmetic number, because the mean of its divisors is an integer number (5177106571).

Almost surely, 2^10354213141 is an apocalyptic number.

It is an amenable number.

10354213141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10354213141 is an equidigital number, since it uses as much as digits as its factorization.

10354213141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 10354213141 its reverse (14131245301), we get a palindrome (24485458442).

The spelling of 10354213141 in words is "ten billion, three hundred fifty-four million, two hundred thirteen thousand, one hundred forty-one".