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10355312279159 is a prime number
BaseRepresentation
bin1001011010110000100010…
…1101011011111001110111
31100122221212111222012020022
42112230020231123321313
52324130134420413114
634005055332155355
72116101202031021
oct226541055337167
940587774865208
1010355312279159
113332732901321
1211b2b19168b5b
135a166a4925a3
1427b2b2311011
1512e57353548e
hex96b08b5be77

10355312279159 has 2 divisors, whose sum is σ = 10355312279160. Its totient is φ = 10355312279158.

The previous prime is 10355312279141. The next prime is 10355312279177. The reversal of 10355312279159 is 95197221355301.

It is a balanced prime because it is at equal distance from previous prime (10355312279141) and next prime (10355312279177).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10355312279159 is a prime.

It is a super-3 number, since 3×103553122791593 (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10355312279159.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10355312278159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177656139579 + 5177656139580.

It is an arithmetic number, because the mean of its divisors is an integer number (5177656139580).

Almost surely, 210355312279159 is an apocalyptic number.

10355312279159 is a deficient number, since it is larger than the sum of its proper divisors (1).

10355312279159 is an equidigital number, since it uses as much as digits as its factorization.

10355312279159 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2551500, while the sum is 53.

The spelling of 10355312279159 in words is "ten trillion, three hundred fifty-five billion, three hundred twelve million, two hundred seventy-nine thousand, one hundred fifty-nine".