103554322412045 has 4 divisors (see below), whose sum is σ = 124265186894460. Its totient is φ = 82843457929632.

The previous prime is 103554322412041. The next prime is 103554322412053. The reversal of 103554322412045 is 540214223455301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 26088589074601 + 77465733337444 = 5107699^2 + 8801462^2 .

It is a cyclic number.

It is not a de Polignac number, because 103554322412045 - 2² = 103554322412041 is a prime.

It is a super-3 number, since 3×103554322412045³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 103554322411993 and 103554322412011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103554322412041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10355432241200 + ... + 10355432241209.

It is an arithmetic number, because the mean of its divisors is an integer number (31066296723615).

Almost surely, 2^{103554322412045} is an apocalyptic number.

It is an amenable number.

103554322412045 is a deficient number, since it is larger than the sum of its proper divisors (20710864482415).

103554322412045 is an equidigital number, since it uses as much as digits as its factorization.

103554322412045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20710864482414.

The product of its (nonzero) digits is 576000, while the sum is 41.

Adding to 103554322412045 its reverse (540214223455301), we get a palindrome (643768545867346).

The spelling of 103554322412045 in words is "one hundred three trillion, five hundred fifty-four billion, three hundred twenty-two million, four hundred twelve thousand, forty-five".