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103633491397 is a prime number
BaseRepresentation
bin110000010000100001…
…0011001010111000101
3100220111101200211102011
41200201002121113011
53144220133211042
6115335241214221
710326064066612
oct1404102312705
9326441624364
10103633491397
113aa50449a57
1218102791371
139a07517a57
14503184b509
152a68214a17
hex18210995c5

103633491397 has 2 divisors, whose sum is σ = 103633491398. Its totient is φ = 103633491396.

The previous prime is 103633491337. The next prime is 103633491431. The reversal of 103633491397 is 793194336301.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74184872161 + 29448619236 = 272369^2 + 171606^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103633491397 is a prime.

It is a super-3 number, since 3×1036334913973 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 103633491397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103633491317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51816745698 + 51816745699.

It is an arithmetic number, because the mean of its divisors is an integer number (51816745699).

Almost surely, 2103633491397 is an apocalyptic number.

It is an amenable number.

103633491397 is a deficient number, since it is larger than the sum of its proper divisors (1).

103633491397 is an equidigital number, since it uses as much as digits as its factorization.

103633491397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1102248, while the sum is 49.

The spelling of 103633491397 in words is "one hundred three billion, six hundred thirty-three million, four hundred ninety-one thousand, three hundred ninety-seven".