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103831241 is a prime number
BaseRepresentation
bin1100011000001…
…01011011001001
321020101011200112
412030011123021
5203040044431
614145244105
72400356663
oct614053311
9236334615
10103831241
1153678a48
122a933635
1318685607
14db0b533
1591aec2b
hex63056c9

103831241 has 2 divisors, whose sum is σ = 103831242. Its totient is φ = 103831240.

The previous prime is 103831237. The next prime is 103831243. The reversal of 103831241 is 142138301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101203600 + 2627641 = 10060^2 + 1621^2 .

It is a cyclic number.

It is not a de Polignac number, because 103831241 - 22 = 103831237 is a prime.

Together with 103831243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (103831243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51915620 + 51915621.

It is an arithmetic number, because the mean of its divisors is an integer number (51915621).

Almost surely, 2103831241 is an apocalyptic number.

It is an amenable number.

103831241 is a deficient number, since it is larger than the sum of its proper divisors (1).

103831241 is an equidigital number, since it uses as much as digits as its factorization.

103831241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

The square root of 103831241 is about 10189.7615771911. The cubic root of 103831241 is about 470.0124351622.

Adding to 103831241 its reverse (142138301), we get a palindrome (245969542).

The spelling of 103831241 in words is "one hundred three million, eight hundred thirty-one thousand, two hundred forty-one".