Search a number
-
+
10401000131 = 232391892123
BaseRepresentation
bin10011010111111001…
…01010101011000011
3222211212022112220002
421223330222223003
5132300124001011
64440025310215
7515514020354
oct115374525303
928755275802
1010401000131
114458103385
12202333536b
13c99abc062
14709507d2b
1540d1bcc3b
hex26bf2aac3

10401000131 has 8 divisors (see below), whose sum is σ = 10898634240. Its totient is φ = 9907150792.

The previous prime is 10401000101. The next prime is 10401000143. The reversal of 10401000131 is 13100010401.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10401000131 - 230 = 9327258307 is a prime.

It is a super-2 number, since 2×104010001312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10401000101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 940565 + ... + 951558.

It is an arithmetic number, because the mean of its divisors is an integer number (1362329280).

Almost surely, 210401000131 is an apocalyptic number.

10401000131 is a deficient number, since it is larger than the sum of its proper divisors (497634109).

10401000131 is a wasteful number, since it uses less digits than its factorization.

10401000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1892385.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 10401000131 its reverse (13100010401), we get a palindrome (23501010532).

The spelling of 10401000131 in words is "ten billion, four hundred one million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 23 239 5497 1892123 43518829 452217397 10401000131