Base | Representation |
---|---|
bin | 10011010111111001… |
… | …01011001000100111 |
3 | 222211212022122111011 |
4 | 21223330223020213 |
5 | 132300124031043 |
6 | 4440025323051 |
7 | 515514026026 |
oct | 115374531047 |
9 | 28755278434 |
10 | 10401002023 |
11 | 4458104845 |
12 | 2023336487 |
13 | c99abcb89 |
14 | 7095088bd |
15 | 40d1bd59d |
hex | 26bf2b227 |
10401002023 has 2 divisors, whose sum is σ = 10401002024. Its totient is φ = 10401002022.
The previous prime is 10401001993. The next prime is 10401002039. The reversal of 10401002023 is 32020010401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10401002023 - 217 = 10400870951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10401001994 and 10401002012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10401002083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200501011 + 5200501012.
It is an arithmetic number, because the mean of its divisors is an integer number (5200501012).
Almost surely, 210401002023 is an apocalyptic number.
10401002023 is a deficient number, since it is larger than the sum of its proper divisors (1).
10401002023 is an equidigital number, since it uses as much as digits as its factorization.
10401002023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 10401002023 its reverse (32020010401), we get a palindrome (42421012424).
The spelling of 10401002023 in words is "ten billion, four hundred one million, two thousand, twenty-three".
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