1040102113 has 4 divisors (see below), whose sum is σ = 1085323968. Its totient is φ = 994880260.

The previous prime is 1040102093. The next prime is 1040102131. The reversal of 1040102113 is 3112010401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1040102113 - 2¹³ = 1040093921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1040102093 and 1040102102.

It is not an unprimeable number, because it can be changed into a prime (1040102213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22610893 + ... + 22610938.

It is an arithmetic number, because the mean of its divisors is an integer number (271330992).

Almost surely, 2^1040102113 is an apocalyptic number.

It is an amenable number.

1040102113 is a deficient number, since it is larger than the sum of its proper divisors (45221855).

1040102113 is an equidigital number, since it uses as much as digits as its factorization.

1040102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45221854.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1040102113 is about 32250.6141491910. The cubic root of 1040102113 is about 1013.1925619485.

Adding to 1040102113 its reverse (3112010401), we get a palindrome (4152112514).

The spelling of 1040102113 in words is "one billion, forty million, one hundred two thousand, one hundred thirteen".