104013021113 has 4 divisors (see below), whose sum is σ = 104016583248. Its totient is φ = 104009458980.

The previous prime is 104013021097. The next prime is 104013021137. The reversal of 104013021113 is 311120310401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 104013021113 - 2⁴ = 104013021097 is a prime.

It is a super-2 number, since 2×104013021113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 104013021091 and 104013021100.

It is not an unprimeable number, because it can be changed into a prime (104013021173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1736903 + ... + 1795788.

It is an arithmetic number, because the mean of its divisors is an integer number (26004145812).

Almost surely, 2^104013021113 is an apocalyptic number.

It is an amenable number.

104013021113 is a deficient number, since it is larger than the sum of its proper divisors (3562135).

104013021113 is an equidigital number, since it uses as much as digits as its factorization.

104013021113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3562134.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 104013021113 its reverse (311120310401), we get a palindrome (415133331514).

The spelling of 104013021113 in words is "one hundred four billion, thirteen million, twenty-one thousand, one hundred thirteen".