1040143433477 has 2 divisors, whose sum is σ = 1040143433478. Its totient is φ = 1040143433476.

The previous prime is 1040143433449. The next prime is 1040143433479. The reversal of 1040143433477 is 7743343410401.

1040143433477 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1007532130081 + 32611303396 = 1003759^2 + 180586^2 .

It is a cyclic number.

It is not a de Polignac number, because 1040143433477 - 2⁸ = 1040143433221 is a prime.

Together with 1040143433479, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1040143433479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520071716738 + 520071716739.

It is an arithmetic number, because the mean of its divisors is an integer number (520071716739).

Almost surely, 2^{1040143433477} is an apocalyptic number.

It is an amenable number.

1040143433477 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040143433477 is an equidigital number, since it uses as much as digits as its factorization.

1040143433477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 338688, while the sum is 41.

Adding to 1040143433477 its reverse (7743343410401), we get a palindrome (8783486843878).

The spelling of 1040143433477 in words is "one trillion, forty billion, one hundred forty-three million, four hundred thirty-three thousand, four hundred seventy-seven".