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10401555415117 is a prime number
BaseRepresentation
bin1001011101011100110100…
…0001000000000001001101
31100211101020021120220020111
42113113031001000001031
52330404341141240432
634042224131120021
72122326145143256
oct227271501000115
940741207526214
1010401555415117
113350302955859
1211bba83a43011
135a5b29abbc29
1427d61badbb2d
1513087d180347
hex975cd04004d

10401555415117 has 2 divisors, whose sum is σ = 10401555415118. Its totient is φ = 10401555415116.

The previous prime is 10401555415093. The next prime is 10401555415127. The reversal of 10401555415117 is 71151455510401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10155573141961 + 245982273156 = 3186781^2 + 495966^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10401555415117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10401555415117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10401555415127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200777707558 + 5200777707559.

It is an arithmetic number, because the mean of its divisors is an integer number (5200777707559).

Almost surely, 210401555415117 is an apocalyptic number.

It is an amenable number.

10401555415117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10401555415117 is an equidigital number, since it uses as much as digits as its factorization.

10401555415117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70000, while the sum is 40.

The spelling of 10401555415117 in words is "ten trillion, four hundred one billion, five hundred fifty-five million, four hundred fifteen thousand, one hundred seventeen".