Base | Representation |
---|---|
bin | 11110010001100110100… |
… | …00101111001101010111 |
3 | 10200110001021001111021102 |
4 | 33020303100233031113 |
5 | 114020403440030234 |
6 | 2113514114340315 |
7 | 135104112024515 |
oct | 17106320571527 |
9 | 3613037044242 |
10 | 1040242111319 |
11 | 371189609834 |
12 | 149732b8a69b |
13 | 7712c55ac28 |
14 | 384c2c394b5 |
15 | 1c0d4624c7e |
hex | f23342f357 |
1040242111319 has 2 divisors, whose sum is σ = 1040242111320. Its totient is φ = 1040242111318.
The previous prime is 1040242111283. The next prime is 1040242111331. The reversal of 1040242111319 is 9131112420401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1040242111319 - 28 = 1040242111063 is a prime.
It is a super-2 number, since 2×10402421113192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1040242111291 and 1040242111300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1040242111339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520121055659 + 520121055660.
It is an arithmetic number, because the mean of its divisors is an integer number (520121055660).
Almost surely, 21040242111319 is an apocalyptic number.
1040242111319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1040242111319 is an equidigital number, since it uses as much as digits as its factorization.
1040242111319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 29.
The spelling of 1040242111319 in words is "one trillion, forty billion, two hundred forty-two million, one hundred eleven thousand, three hundred nineteen".
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