1040242111331 has 2 divisors, whose sum is σ = 1040242111332. Its totient is φ = 1040242111330.

The previous prime is 1040242111319. The next prime is 1040242111339. The reversal of 1040242111331 is 1331112420401.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1040242111331 is a prime.

It is a super-2 number, since 2×1040242111331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1040242111297 and 1040242111306.

It is not a weakly prime, because it can be changed into another prime (1040242111339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520121055665 + 520121055666.

It is an arithmetic number, because the mean of its divisors is an integer number (520121055666).

Almost surely, 2^{1040242111331} is an apocalyptic number.

1040242111331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040242111331 is an equidigital number, since it uses as much as digits as its factorization.

1040242111331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1040242111331 its reverse (1331112420401), we get a palindrome (2371354531732).

The spelling of 1040242111331 in words is "one trillion, forty billion, two hundred forty-two million, one hundred eleven thousand, three hundred thirty-one".