10403113420221 has 4 divisors (see below), whose sum is σ = 13870817893632. Its totient is φ = 6935408946812.

The previous prime is 10403113420211. The next prime is 10403113420253. The reversal of 10403113420221 is 12202431130401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10403113420221 - 2¹⁰ = 10403113419197 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10403113420191 and 10403113420200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10403113420211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1733852236701 + ... + 1733852236706.

It is an arithmetic number, because the mean of its divisors is an integer number (3467704473408).

Almost surely, 2^{10403113420221} is an apocalyptic number.

It is an amenable number.

10403113420221 is a deficient number, since it is larger than the sum of its proper divisors (3467704473411).

10403113420221 is an equidigital number, since it uses as much as digits as its factorization.

10403113420221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3467704473410.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 10403113420221 its reverse (12202431130401), we get a palindrome (22605544550622).

The spelling of 10403113420221 in words is "ten trillion, four hundred three billion, one hundred thirteen million, four hundred twenty thousand, two hundred twenty-one".