Base | Representation |
---|---|
bin | 10011011001001110… |
… | …00110000100110111 |
3 | 222212122020121210211 |
4 | 21230213012010313 |
5 | 132311000404143 |
6 | 4441103530251 |
7 | 516010403023 |
oct | 115447060467 |
9 | 28778217724 |
10 | 10412122423 |
11 | 446340a75a |
12 | 2026bb9987 |
13 | c9c1b46b1 |
14 | 70aba1383 |
15 | 40e16849d |
hex | 26c9c6137 |
10412122423 has 2 divisors, whose sum is σ = 10412122424. Its totient is φ = 10412122422.
The previous prime is 10412122411. The next prime is 10412122429. The reversal of 10412122423 is 32422121401.
10412122423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10412122423 - 233 = 1822187831 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10412122394 and 10412122403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10412122429) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206061211 + 5206061212.
It is an arithmetic number, because the mean of its divisors is an integer number (5206061212).
Almost surely, 210412122423 is an apocalyptic number.
10412122423 is a deficient number, since it is larger than the sum of its proper divisors (1).
10412122423 is an equidigital number, since it uses as much as digits as its factorization.
10412122423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 10412122423 its reverse (32422121401), we get a palindrome (42834243824).
The spelling of 10412122423 in words is "ten billion, four hundred twelve million, one hundred twenty-two thousand, four hundred twenty-three".
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