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1041312045551 = 6607157607393
BaseRepresentation
bin11110010011100110000…
…10001101100111101111
310200112210211022210010012
433021303002031213233
5114030101340424201
62114212215003435
7135142453226351
oct17116302154757
93615724283105
101041312045551
113716885591a8
1214999136957b
13772701129cb
1438584d8d0d1
151c14851c5bb
hexf27308d9ef

1041312045551 has 4 divisors (see below), whose sum is σ = 1041469659552. Its totient is φ = 1041154431552.

The previous prime is 1041312045523. The next prime is 1041312045607. The reversal of 1041312045551 is 1555402131401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1041312045551 - 222 = 1041307851247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1041312045511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78797090 + ... + 78810303.

It is an arithmetic number, because the mean of its divisors is an integer number (260367414888).

Almost surely, 21041312045551 is an apocalyptic number.

1041312045551 is a deficient number, since it is larger than the sum of its proper divisors (157614001).

1041312045551 is an equidigital number, since it uses as much as digits as its factorization.

1041312045551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157614000.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 1041312045551 its reverse (1555402131401), we get a palindrome (2596714176952).

The spelling of 1041312045551 in words is "one trillion, forty-one billion, three hundred twelve million, forty-five thousand, five hundred fifty-one".

Divisors: 1 6607 157607393 1041312045551