Base | Representation |
---|---|
bin | 1001011110001000011001… |
… | …0100111100110011110011 |
3 | 1100212111102121020002122111 |
4 | 2113202012110330303303 |
5 | 2331102321104130103 |
6 | 34051441044150151 |
7 | 2123222102443162 |
oct | 227420624746363 |
9 | 40774377202574 |
10 | 10413254364403 |
11 | 3355266685590 |
12 | 12021a9998357 |
13 | 5a6c72778627 |
14 | 28000b7513d9 |
15 | 130d1528586d |
hex | 9788653ccf3 |
10413254364403 has 8 divisors (see below), whose sum is σ = 11487553334640. Its totient is φ = 9360228641280.
The previous prime is 10413254364391. The next prime is 10413254364497. The reversal of 10413254364403 is 30446345231401.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10413254364403 - 217 = 10413254233331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10413258364403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5318310750 + ... + 5318312707.
It is an arithmetic number, because the mean of its divisors is an integer number (1435944166830).
Almost surely, 210413254364403 is an apocalyptic number.
10413254364403 is a deficient number, since it is larger than the sum of its proper divisors (1074298970237).
10413254364403 is a wasteful number, since it uses less digits than its factorization.
10413254364403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10636623557.
The product of its (nonzero) digits is 414720, while the sum is 40.
Adding to 10413254364403 its reverse (30446345231401), we get a palindrome (40859599595804).
The spelling of 10413254364403 in words is "ten trillion, four hundred thirteen billion, two hundred fifty-four million, three hundred sixty-four thousand, four hundred three".
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