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10413524050213 is a prime number
BaseRepresentation
bin1001011110001001011001…
…1001101110000100100101
31100212112010101200120000211
42113202112121232010211
52331103344124101323
634051523520335421
72123231555645164
oct227422631560445
940775111616024
1010413524050213
113355394934519
121202264174571
135a6cb65c142b
142800354b33db
15130d2dca770d
hex9789666e125

10413524050213 has 2 divisors, whose sum is σ = 10413524050214. Its totient is φ = 10413524050212.

The previous prime is 10413524050207. The next prime is 10413524050219. The reversal of 10413524050213 is 31205042531401.

It is a balanced prime because it is at equal distance from previous prime (10413524050207) and next prime (10413524050219).

It can be written as a sum of positive squares in only one way, i.e., 6425043744289 + 3988480305924 = 2534767^2 + 1997118^2 .

It is a cyclic number.

It is not a de Polignac number, because 10413524050213 - 221 = 10413521953061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10413524050219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206762025106 + 5206762025107.

It is an arithmetic number, because the mean of its divisors is an integer number (5206762025107).

Almost surely, 210413524050213 is an apocalyptic number.

It is an amenable number.

10413524050213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10413524050213 is an equidigital number, since it uses as much as digits as its factorization.

10413524050213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 10413524050213 its reverse (31205042531401), we get a palindrome (41618566581614).

The spelling of 10413524050213 in words is "ten trillion, four hundred thirteen billion, five hundred twenty-four million, fifty thousand, two hundred thirteen".