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10414421314303 is a prime number
BaseRepresentation
bin1001011110001100101111…
…1000100000101011111111
31100212121102221001021222011
42113203023320200223333
52331112213324024203
634052152532032051
72123263032400366
oct227431370405377
940777387037864
1010414421314303
113355805368296
121202474762627
135a70ca46a726
142800bc71a7dd
15130d8294376d
hex978cbe20aff

10414421314303 has 2 divisors, whose sum is σ = 10414421314304. Its totient is φ = 10414421314302.

The previous prime is 10414421314301. The next prime is 10414421314309. The reversal of 10414421314303 is 30341312441401.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10414421314303 - 21 = 10414421314301 is a prime.

Together with 10414421314301, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10414421314301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5207210657151 + 5207210657152.

It is an arithmetic number, because the mean of its divisors is an integer number (5207210657152).

Almost surely, 210414421314303 is an apocalyptic number.

10414421314303 is a deficient number, since it is larger than the sum of its proper divisors (1).

10414421314303 is an equidigital number, since it uses as much as digits as its factorization.

10414421314303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 10414421314303 its reverse (30341312441401), we get a palindrome (40755733755704).

The spelling of 10414421314303 in words is "ten trillion, four hundred fourteen billion, four hundred twenty-one million, three hundred fourteen thousand, three hundred three".