Base | Representation |
---|---|
bin | 10011011010011100… |
… | …10110000100111101 |
3 | 222220100121100212202 |
4 | 21231032112010331 |
5 | 132321114132311 |
6 | 4442112241245 |
7 | 516164015411 |
oct | 115516260475 |
9 | 28810540782 |
10 | 10422411581 |
11 | 44691a809a |
12 | 202a540225 |
13 | ca1377a5a |
14 | 70c2bcd41 |
15 | 40eeebe3b |
hex | 26d39613d |
10422411581 has 2 divisors, whose sum is σ = 10422411582. Its totient is φ = 10422411580.
The previous prime is 10422411557. The next prime is 10422411611. The reversal of 10422411581 is 18511422401.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9122160100 + 1300251481 = 95510^2 + 36059^2 .
It is a cyclic number.
It is not a de Polignac number, because 10422411581 - 214 = 10422395197 is a prime.
It is a super-2 number, since 2×104224115812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10422411511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211205790 + 5211205791.
It is an arithmetic number, because the mean of its divisors is an integer number (5211205791).
Almost surely, 210422411581 is an apocalyptic number.
It is an amenable number.
10422411581 is a deficient number, since it is larger than the sum of its proper divisors (1).
10422411581 is an equidigital number, since it uses as much as digits as its factorization.
10422411581 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 29.
Adding to 10422411581 its reverse (18511422401), we get a palindrome (28933833982).
The spelling of 10422411581 in words is "ten billion, four hundred twenty-two million, four hundred eleven thousand, five hundred eighty-one".
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