1042524401 has 2 divisors, whose sum is σ = 1042524402. Its totient is φ = 1042524400.

The previous prime is 1042524397. The next prime is 1042524403. The reversal of 1042524401 is 1044252401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 993510400 + 49014001 = 31520^2 + 7001^2 .

It is an emirp because it is prime and its reverse (1044252401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1042524401 - 2² = 1042524397 is a prime.

It is a Sophie Germain prime.

Together with 1042524403, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1042524403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521262200 + 521262201.

It is an arithmetic number, because the mean of its divisors is an integer number (521262201).

Almost surely, 2^1042524401 is an apocalyptic number.

It is an amenable number.

1042524401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1042524401 is an equidigital number, since it uses as much as digits as its factorization.

1042524401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1280, while the sum is 23.

The square root of 1042524401 is about 32288.1464472645. The cubic root of 1042524401 is about 1013.9784916471.

Adding to 1042524401 its reverse (1044252401), we get a palindrome (2086776802).

Subtracting 1042524401 from its reverse (1044252401), we obtain a cube (1728000 = 120³).

The spelling of 1042524401 in words is "one billion, forty-two million, five hundred twenty-four thousand, four hundred one".