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1043313301055 = 5641869337447
BaseRepresentation
bin11110010111010100101…
…00011001011000111111
310200201222022001002120102
433023222110121120333
5114043201201113210
62115142544511315
7135243163510454
oct17135224313077
93621868032512
101043313301055
11372515183073
1214a24b61b53b
13774cb90966c
14386d4a9382b
151c21407bea5
hexf2ea51963f

1043313301055 has 16 divisors (see below), whose sum is σ = 1254106857024. Its totient is φ = 833230417920.

The previous prime is 1043313301013. The next prime is 1043313301061. The reversal of 1043313301055 is 5501033133401.

It is not a de Polignac number, because 1043313301055 - 210 = 1043313300031 is a prime.

It is a super-2 number, since 2×10433133010552 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27842342 + ... + 27879788.

It is an arithmetic number, because the mean of its divisors is an integer number (78381678564).

Almost surely, 21043313301055 is an apocalyptic number.

1043313301055 is a deficient number, since it is larger than the sum of its proper divisors (210793555969).

1043313301055 is an equidigital number, since it uses as much as digits as its factorization.

1043313301055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46786.

The product of its (nonzero) digits is 8100, while the sum is 29.

Adding to 1043313301055 its reverse (5501033133401), we get a palindrome (6544346434456).

The spelling of 1043313301055 in words is "one trillion, forty-three billion, three hundred thirteen million, three hundred one thousand, fifty-five".

Divisors: 1 5 641 3205 8693 37447 43465 187235 5572213 24003527 27861065 120017635 325526771 1627633855 208662660211 1043313301055