Base | Representation |
---|---|
bin | 110000100101011100… |
… | …0011101110101010111 |
3 | 100222022022201011011221 |
4 | 1201022320131311113 |
5 | 3202134344000401 |
6 | 115533040311211 |
7 | 10352350245412 |
oct | 1411270356527 |
9 | 328268634157 |
10 | 104335531351 |
11 | 40280761a67 |
12 | 18279912507 |
13 | 9ab9abc7cc |
14 | 509ab96b79 |
15 | 2aa9b8b7a1 |
hex | 184ae1dd57 |
104335531351 has 2 divisors, whose sum is σ = 104335531352. Its totient is φ = 104335531350.
The previous prime is 104335531283. The next prime is 104335531409. The reversal of 104335531351 is 153135533401.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 104335531351 - 235 = 69975792983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104330531351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52167765675 + 52167765676.
It is an arithmetic number, because the mean of its divisors is an integer number (52167765676).
Almost surely, 2104335531351 is an apocalyptic number.
104335531351 is a deficient number, since it is larger than the sum of its proper divisors (1).
104335531351 is an equidigital number, since it uses as much as digits as its factorization.
104335531351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 34.
The spelling of 104335531351 in words is "one hundred four billion, three hundred thirty-five million, five hundred thirty-one thousand, three hundred fifty-one".
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