10434115 has 4 divisors (see below), whose sum is σ = 12520944. Its totient is φ = 8347288.

The previous prime is 10434103. The next prime is 10434121. The reversal of 10434115 is 51143401.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51143401 = 3709 ⋅13789.

It is a cyclic number.

It is not a de Polignac number, because 10434115 - 2⁷ = 10433987 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10434092 and 10434101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1043407 + ... + 1043416.

It is an arithmetic number, because the mean of its divisors is an integer number (3130236).

Almost surely, 2^10434115 is an apocalyptic number.

10434115 is a deficient number, since it is larger than the sum of its proper divisors (2086829).

10434115 is an equidigital number, since it uses as much as digits as its factorization.

10434115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2086828.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 10434115 is about 3230.1880750198. The cubic root of 10434115 is about 218.5169883476.

Adding to 10434115 its reverse (51143401), we get a palindrome (61577516).

The spelling of 10434115 in words is "ten million, four hundred thirty-four thousand, one hundred fifteen".