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104513112113 = 432430537491
BaseRepresentation
bin110000101010101110…
…1111000100000110001
3100222202200212012012012
41201111131320200301
53203020324041423
6120002422412305
710356634536524
oct1412535704061
9328680765165
10104513112113
1140361a22023
1218309291095
139b17827497
1450b65c0bbb
152aba568078
hex1855778831

104513112113 has 4 divisors (see below), whose sum is σ = 106943649648. Its totient is φ = 102082574580.

The previous prime is 104513112097. The next prime is 104513112169. The reversal of 104513112113 is 311211315401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 104513112113 - 24 = 104513112097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (104513111113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1215268703 + ... + 1215268788.

It is an arithmetic number, because the mean of its divisors is an integer number (26735912412).

Almost surely, 2104513112113 is an apocalyptic number.

It is an amenable number.

104513112113 is a deficient number, since it is larger than the sum of its proper divisors (2430537535).

104513112113 is an equidigital number, since it uses as much as digits as its factorization.

104513112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2430537534.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 104513112113 its reverse (311211315401), we get a palindrome (415724427514).

The spelling of 104513112113 in words is "one hundred four billion, five hundred thirteen million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 43 2430537491 104513112113