10452134113 has 4 divisors (see below), whose sum is σ = 10504657600. Its totient is φ = 10399610628.

The previous prime is 10452134083. The next prime is 10452134129. The reversal of 10452134113 is 31143125401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31143125401 = 17 ⋅1831948553.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10452134113 is a prime.

It is a super-2 number, since 2×10452134113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10452134183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26261445 + ... + 26261842.

It is an arithmetic number, because the mean of its divisors is an integer number (2626164400).

Almost surely, 2^10452134113 is an apocalyptic number.

It is an amenable number.

10452134113 is a deficient number, since it is larger than the sum of its proper divisors (52523487).

10452134113 is an equidigital number, since it uses as much as digits as its factorization.

10452134113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52523486.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 10452134113 its reverse (31143125401), we get a palindrome (41595259514).

The spelling of 10452134113 in words is "ten billion, four hundred fifty-two million, one hundred thirty-four thousand, one hundred thirteen".