31143125401 has 4 divisors (see below), whose sum is σ = 32975073972. Its totient is φ = 29311176832.

The previous prime is 31143125393. The next prime is 31143125411. The reversal of 31143125401 is 10452134113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10452134113 = 199 ⋅52523287.

It can be written as a sum of positive squares in 2 ways, for example, as 18056909376 + 13086216025 = 134376^2 + 114395^2 .

It is a cyclic number.

It is not a de Polignac number, because 31143125401 - 2³ = 31143125393 is a prime.

It is a super-2 number, since 2×31143125401² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31143125411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 915974260 + ... + 915974293.

It is an arithmetic number, because the mean of its divisors is an integer number (8243768493).

Almost surely, 2^31143125401 is an apocalyptic number.

It is an amenable number.

31143125401 is a deficient number, since it is larger than the sum of its proper divisors (1831948571).

31143125401 is a wasteful number, since it uses less digits than its factorization.

31143125401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1831948570.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 31143125401 its reverse (10452134113), we get a palindrome (41595259514).

The spelling of 31143125401 in words is "thirty-one billion, one hundred forty-three million, one hundred twenty-five thousand, four hundred one".