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1045511431 is a prime number
BaseRepresentation
bin111110010100010…
…011110100000111
32200212022111001121
4332110103310013
54120122331211
6251424534411
734623462166
oct7624236407
92625274047
101045511431
11497189238
12252181407
131387b3523
149cbd73dd
1561bc1271
hex3e513d07

1045511431 has 2 divisors, whose sum is σ = 1045511432. Its totient is φ = 1045511430.

The previous prime is 1045511429. The next prime is 1045511459. The reversal of 1045511431 is 1341155401.

It is a weak prime.

It is an emirp because it is prime and its reverse (1341155401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1045511431 - 21 = 1045511429 is a prime.

It is a super-2 number, since 2×10455114312 = 2186188304703335522, which contains 22 as substring.

Together with 1045511429, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1045511396 and 1045511405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1045511471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 522755715 + 522755716.

It is an arithmetic number, because the mean of its divisors is an integer number (522755716).

Almost surely, 21045511431 is an apocalyptic number.

1045511431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1045511431 is an equidigital number, since it uses as much as digits as its factorization.

1045511431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

The square root of 1045511431 is about 32334.3691913110. The cubic root of 1045511431 is about 1014.9459817402.

Adding to 1045511431 its reverse (1341155401), we get a palindrome (2386666832).

The spelling of 1045511431 in words is "one billion, forty-five million, five hundred eleven thousand, four hundred thirty-one".