Search a number
-
+
10491904373 is a prime number
BaseRepresentation
bin10011100010101110…
…11100000101110101
31000002012100222001212
421301113130011311
5132441411414443
64453033531205
7520666500326
oct116127340565
930065328055
1010491904373
1144a4452055
122049873b05
13cb2899752
1471760c44d
15416177618
hex2715dc175

10491904373 has 2 divisors, whose sum is σ = 10491904374. Its totient is φ = 10491904372.

The previous prime is 10491904309. The next prime is 10491904427. The reversal of 10491904373 is 37340919401.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9921554449 + 570349924 = 99607^2 + 23882^2 .

It is a cyclic number.

It is not a de Polignac number, because 10491904373 - 26 = 10491904309 is a prime.

It is a super-2 number, since 2×104919043732 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10491904373.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10491904303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5245952186 + 5245952187.

It is an arithmetic number, because the mean of its divisors is an integer number (5245952187).

Almost surely, 210491904373 is an apocalyptic number.

It is an amenable number.

10491904373 is a deficient number, since it is larger than the sum of its proper divisors (1).

10491904373 is an equidigital number, since it uses as much as digits as its factorization.

10491904373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 41.

The spelling of 10491904373 in words is "ten billion, four hundred ninety-one million, nine hundred four thousand, three hundred seventy-three".