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104932081353 = 3113179760041
BaseRepresentation
bin110000110111001110…
…0000111111011001001
3101000211220020000221110
41201232130013323021
53204400103100403
6120112150400533
710403212655301
oct1415634077311
9330756200843
10104932081353
11405574738a0
1218405660149
139b8357ac88
1451160c2601
152ae2227103
hex186e707ec9

104932081353 has 8 divisors (see below), whose sum is σ = 152628482016. Its totient is φ = 63595200800.

The previous prime is 104932081291. The next prime is 104932081367. The reversal of 104932081353 is 353180239401.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 104932081353 - 210 = 104932080329 is a prime.

It is a super-2 number, since 2×1049320813532 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (104932581353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1589879988 + ... + 1589880053.

It is an arithmetic number, because the mean of its divisors is an integer number (19078560252).

Almost surely, 2104932081353 is an apocalyptic number.

It is an amenable number.

104932081353 is a deficient number, since it is larger than the sum of its proper divisors (47696400663).

104932081353 is a wasteful number, since it uses less digits than its factorization.

104932081353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3179760055.

The product of its (nonzero) digits is 77760, while the sum is 39.

The spelling of 104932081353 in words is "one hundred four billion, nine hundred thirty-two million, eighty-one thousand, three hundred fifty-three".

Divisors: 1 3 11 33 3179760041 9539280123 34977360451 104932081353