1049411983 has 2 divisors, whose sum is σ = 1049411984. Its totient is φ = 1049411982.

The previous prime is 1049411981. The next prime is 1049412017. The reversal of 1049411983 is 3891149401.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1049411983 - 2¹ = 1049411981 is a prime.

It is a super-2 number, since 2×1049411983² = 2202531020127984578, which contains 22 as substring.

Together with 1049411981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1049411981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 524705991 + 524705992.

It is an arithmetic number, because the mean of its divisors is an integer number (524705992).

Almost surely, 2^1049411983 is an apocalyptic number.

1049411983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1049411983 is an equidigital number, since it uses as much as digits as its factorization.

1049411983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 40.

The square root of 1049411983 is about 32394.6289220914. The cubic root of 1049411983 is about 1016.2065885808.

The spelling of 1049411983 in words is "one billion, forty-nine million, four hundred eleven thousand, nine hundred eighty-three".