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10500651113 is a prime number
BaseRepresentation
bin10011100011110001…
…10011100001101001
31000002210211100100012
421301320303201221
5133001131313423
64453545221305
7521134030121
oct116170634151
930083740305
1010500651113
1144a9386667
122050791835
13cb463ca34
14718847c81
15416d04078
hex271e33869

10500651113 has 2 divisors, whose sum is σ = 10500651114. Its totient is φ = 10500651112.

The previous prime is 10500651101. The next prime is 10500651223. The reversal of 10500651113 is 31115600501.

10500651113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6650076304 + 3850574809 = 81548^2 + 62053^2 .

It is a cyclic number.

It is not a de Polignac number, because 10500651113 - 28 = 10500650857 is a prime.

It is a super-2 number, since 2×105006511132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10500671113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5250325556 + 5250325557.

It is an arithmetic number, because the mean of its divisors is an integer number (5250325557).

Almost surely, 210500651113 is an apocalyptic number.

It is an amenable number.

10500651113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10500651113 is an equidigital number, since it uses as much as digits as its factorization.

10500651113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 23.

The spelling of 10500651113 in words is "ten billion, five hundred million, six hundred fifty-one thousand, one hundred thirteen".