Base | Representation |
---|---|
bin | 11110100011111110111… |
… | …11110000010011110111 |
3 | 10201101112001012120102212 |
4 | 33101333133300103313 |
5 | 114201111412112444 |
6 | 2122225300124035 |
7 | 135603505441433 |
oct | 17217737602367 |
9 | 3641461176385 |
10 | 1050111050999 |
11 | 37539334822a |
12 | 14b62809661b |
13 | 7804304b0ca |
14 | 38b7b8039c3 |
15 | 1c4b0c4519e |
hex | f47f7f04f7 |
1050111050999 has 2 divisors, whose sum is σ = 1050111051000. Its totient is φ = 1050111050998.
The previous prime is 1050111050987. The next prime is 1050111051001. The reversal of 1050111050999 is 9990501110501.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1050111050999 is a prime.
It is a super-2 number, since 2×10501110509992 (a number of 25 digits) contains 22 as substring.
Together with 1050111051001, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1050111052999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525055525499 + 525055525500.
It is an arithmetic number, because the mean of its divisors is an integer number (525055525500).
Almost surely, 21050111050999 is an apocalyptic number.
1050111050999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1050111050999 is an equidigital number, since it uses as much as digits as its factorization.
1050111050999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18225, while the sum is 41.
The spelling of 1050111050999 in words is "one trillion, fifty billion, one hundred eleven million, fifty thousand, nine hundred ninety-nine".
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