Base | Representation |
---|---|
bin | 11110100100000001100… |
… | …01011001111011011111 |
3 | 10201101120112111000101122 |
4 | 33102000301121323133 |
5 | 114201132402031020 |
6 | 2122231343001155 |
7 | 135604155406241 |
oct | 17220061317337 |
9 | 3641515430348 |
10 | 1050132455135 |
11 | 3753a44374a5 |
12 | 14b6332991bb |
13 | 7804760368a |
14 | 38b805b6091 |
15 | 1c4b2a72125 |
hex | f480c59edf |
1050132455135 has 16 divisors (see below), whose sum is σ = 1263351794400. Its totient is φ = 837977765376.
The previous prime is 1050132455077. The next prime is 1050132455149. The reversal of 1050132455135 is 5315542310501.
It is a cyclic number.
It is not a de Polignac number, because 1050132455135 - 28 = 1050132454879 is a prime.
It is a super-2 number, since 2×10501324551352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1050132455095 and 1050132455104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43151651 + ... + 43175979.
It is an arithmetic number, because the mean of its divisors is an integer number (78959487150).
Almost surely, 21050132455135 is an apocalyptic number.
1050132455135 is a deficient number, since it is larger than the sum of its proper divisors (213219339265).
1050132455135 is a wasteful number, since it uses less digits than its factorization.
1050132455135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45850.
The product of its (nonzero) digits is 45000, while the sum is 35.
Adding to 1050132455135 its reverse (5315542310501), we get a palindrome (6365674765636).
The spelling of 1050132455135 in words is "one trillion, fifty billion, one hundred thirty-two million, four hundred fifty-five thousand, one hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •