Base | Representation |
---|---|
bin | 10011100100000100… |
… | …10011111110010001 |
3 | 1000002222111221222220 |
4 | 21302002103332101 |
5 | 133002301041223 |
6 | 4454114451253 |
7 | 521164150035 |
oct | 116202237621 |
9 | 30088457886 |
10 | 10503143313 |
11 | 44aa829033 |
12 | 2051593b29 |
13 | cb5003200 |
14 | 718cd61c5 |
15 | 4171476e3 |
hex | 272093f91 |
10503143313 has 24 divisors (see below), whose sum is σ = 15201678240. Its totient is φ = 6447542400.
The previous prime is 10503143309. The next prime is 10503143327. The reversal of 10503143313 is 31334130501.
It is not a de Polignac number, because 10503143313 - 22 = 10503143309 is a prime.
It is a super-2 number, since 2×105031433132 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (10503142313) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 182038 + ... + 232688.
It is an arithmetic number, because the mean of its divisors is an integer number (633403260).
Almost surely, 210503143313 is an apocalyptic number.
10503143313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10503143313 is a deficient number, since it is larger than the sum of its proper divisors (4698534927).
10503143313 is a wasteful number, since it uses less digits than its factorization.
10503143313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51089 (or 51076 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 10503143313 its reverse (31334130501), we get a palindrome (41837273814).
The spelling of 10503143313 in words is "ten billion, five hundred three million, one hundred forty-three thousand, three hundred thirteen".
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