Search a number
-
+
10503143313 = 313240950651
BaseRepresentation
bin10011100100000100…
…10011111110010001
31000002222111221222220
421302002103332101
5133002301041223
64454114451253
7521164150035
oct116202237621
930088457886
1010503143313
1144aa829033
122051593b29
13cb5003200
14718cd61c5
154171476e3
hex272093f91

10503143313 has 24 divisors (see below), whose sum is σ = 15201678240. Its totient is φ = 6447542400.

The previous prime is 10503143309. The next prime is 10503143327. The reversal of 10503143313 is 31334130501.

It is not a de Polignac number, because 10503143313 - 22 = 10503143309 is a prime.

It is a super-2 number, since 2×105031433132 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10503142313) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 182038 + ... + 232688.

It is an arithmetic number, because the mean of its divisors is an integer number (633403260).

Almost surely, 210503143313 is an apocalyptic number.

10503143313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10503143313 is a deficient number, since it is larger than the sum of its proper divisors (4698534927).

10503143313 is a wasteful number, since it uses less digits than its factorization.

10503143313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51089 (or 51076 counting only the distinct ones).

The product of its (nonzero) digits is 1620, while the sum is 24.

Adding to 10503143313 its reverse (31334130501), we get a palindrome (41837273814).

The spelling of 10503143313 in words is "ten billion, five hundred three million, one hundred forty-three thousand, three hundred thirteen".

Divisors: 1 3 13 39 169 409 507 1227 5317 15951 50651 69121 151953 207363 658463 1975389 8560019 20716259 25680057 62148777 269311367 807934101 3501047771 10503143313