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105044112535 = 522991741583
BaseRepresentation
bin110000111010100011…
…1011111010010010111
3101001010201000210211111
41201311013133102113
53210112243100120
6120131231515451
710406043136645
oct1416507372227
9331121023744
10105044112535
114060473254a
1218437088b87
139ba0844a0b
145126d26195
152aebea675a
hex18751df497

105044112535 has 8 divisors (see below), whose sum is σ = 126603385920. Its totient is φ = 83668322784.

The previous prime is 105044112487. The next prime is 105044112581. The reversal of 105044112535 is 535211440501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 105044112535 - 221 = 105042015383 is a prime.

It is a super-2 number, since 2×1050441125352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105044112497 and 105044112506.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45869647 + ... + 45871936.

It is an arithmetic number, because the mean of its divisors is an integer number (15825423240).

Almost surely, 2105044112535 is an apocalyptic number.

105044112535 is a deficient number, since it is larger than the sum of its proper divisors (21559273385).

105044112535 is an equidigital number, since it uses as much as digits as its factorization.

105044112535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91741817.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 105044112535 in words is "one hundred five billion, forty-four million, one hundred twelve thousand, five hundred thirty-five".

Divisors: 1 5 229 1145 91741583 458707915 21008822507 105044112535