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10505000141 is a prime number
BaseRepresentation
bin10011100100010010…
…11001010011001101
31000010010000022002022
421302021121103031
5133003240001031
64454222335525
7521216012366
oct116211312315
930103008068
1010505000141
1145008870a9
12205212a5a5
13cb550341c
1471925ab6d
154173b297b
hex2722594cd

10505000141 has 2 divisors, whose sum is σ = 10505000142. Its totient is φ = 10505000140.

The previous prime is 10505000131. The next prime is 10505000239. The reversal of 10505000141 is 14100050501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7722015625 + 2782984516 = 87875^2 + 52754^2 .

It is an emirp because it is prime and its reverse (14100050501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10505000141 is a prime.

It is a super-2 number, since 2×105050001412 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10505000131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5252500070 + 5252500071.

It is an arithmetic number, because the mean of its divisors is an integer number (5252500071).

Almost surely, 210505000141 is an apocalyptic number.

It is an amenable number.

10505000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10505000141 is an equidigital number, since it uses as much as digits as its factorization.

10505000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 100, while the sum is 17.

Adding to 10505000141 its reverse (14100050501), we get a palindrome (24605050642).

The spelling of 10505000141 in words is "ten billion, five hundred five million, one hundred forty-one", and thus it is an aban number.