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105052903 is a prime number
BaseRepresentation
bin1100100001011…
…11101011100111
321022200020111021
412100233223213
5203343143103
614231352011
72413635454
oct620575347
9238606437
10105052903
115433288a
122b222607
13189c26a7
14dd4882b
159351bbd
hex642fae7

105052903 has 2 divisors, whose sum is σ = 105052904. Its totient is φ = 105052902.

The previous prime is 105052901. The next prime is 105052907. The reversal of 105052903 is 309250501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 105052903 - 21 = 105052901 is a prime.

It is a super-3 number, since 3×1050529033 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 105052901, it forms a pair of twin primes.

It is an alternating number because its digits alternate between odd and even.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105052901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52526451 + 52526452.

It is an arithmetic number, because the mean of its divisors is an integer number (52526452).

Almost surely, 2105052903 is an apocalyptic number.

105052903 is a deficient number, since it is larger than the sum of its proper divisors (1).

105052903 is an equidigital number, since it uses as much as digits as its factorization.

105052903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 25.

The square root of 105052903 is about 10249.5318429673. The cubic root of 105052903 is about 471.8486165270.

The spelling of 105052903 in words is "one hundred five million, fifty-two thousand, nine hundred three".